A 40 kg slab rests on a frictionless floor. A 10 kg block rests on top of the slab as shown in the figure. The coefficient of static friction between the block and slab is 0.60 and coefficient of kine

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A 40 kg slab rests on a frictionless floor. A 10 kg block rests on top of the slab as shown in the figure. The coefficient of static friction between the block and slab is 0.60 and coefficient of kinetic friction is 0.40 . The 10 kg block is acted upon by a horizontal force of 100 N. The resulting acceleration of slab will be: (Take g = 10 m/s²)

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Maximum static friction = 0.6 × 10 × 10 = 60 N . Moving together would require a = 50 100 ​ = 2 m/ s 2 and friction 40 × 2 = 80 N > 60 N, so the block slips. Kinetic friction = 0.4 × 100 = 40 N drives the slab a = 40 40 ​ = 1 m/ s 2 . Option A.

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