A light string is fixed to a rigid support, passes under a light movable pulley carrying a block of mass m , and then passes over a fixed light pulley; the free end of the string is pulled vertically

Question

A light string is fixed to a rigid support, passes under a light movable pulley carrying a block of mass $m$ , and then passes over a fixed light pulley; the free end of the string is pulled vertically downward with force $F = 2 m g$ . Pulleys and string are massless. The acceleration of the block is:

Options:

Answer:

A

Solution:

$T = 2 m g$
$2 T - m g = ma$
gives
$4 m g - m g = ma$
so
$a = 3 g .$
Option A.

TestHub · Accepted Answer

T = 2 m g 2 T − m g = ma gives 4 m g − m g = ma so a = 3 g . Option A.

Physics - NLM Question with Solution | TestHub

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