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PhysicsNLMFBD & EquilibriumMedium2 minQB

PhysicsMediummultiple choice

Two blocks are kept in contact as shown in figure. Find

Answer:

A, B, D

Solution:

$F_{H} = 50 sin 3 0^{\circ} = 25 N$

$F_{V} = 50 cos 3 0^{\circ} = 43.3 N$

$F_{c} = 100 N$ ⟹ (B)

$N_{1} = 10 g = 100 N$ ⟹(D )

Downward forces:

$20 g + 43.3 = 200 + 43.3 = 243.3 N$

$N_{2} = 243.3 N$ ⟹(A)

Answer: A, B, D

Stream:JEESubject:PhysicsTopic:NLMSubtopic:FBD & Equilibrium

⏱ 2mℹ️ Source: QB

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