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Physics - NLM Question with Solution | TestHub

PhysicsNLMMiscellaneousMedium2 minQB

PhysicsMediumsingle choice

A particle of mass m is made to move with a uniform speed $v_{0}$ along the perimeter of a regular hexagon. The magnitude of impulse applied at each corner of the hexagon is

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Answer:

Solution:

$\overset{v}{ˉ}_{2} = v_{0} cos 60 \hat{i} + v_{0} sin 60 \hat{j} Impulse = m (\overset{v}{ˉ}_{2} - \overset{v}{ˉ}_{1})$

$= m [\frac{- v _{0}}{2} \hat{i} + \frac{v _{0} 3}{2} \hat{j}$

$∴ Impulse = mv_{0}$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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