A block of mass M placed inside a box descends vertically with acceleration a . The block exerts a force equal to one-fourth of its weight on the floor of the box. The value of ' a ' will be

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The forces acting on the block are shown below.

Here, $N$ is normal force and box is falling with acceleration $a$ .

From figure, $M g - N = M a$

According to question, $N = \frac{M g}{4}$

$\frac{M g}{4} = M (g - a)$

$\Rightarrow a = \frac{3 g}{4}$

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