Physics - NLM Question with Solution | TestHub

The block moves down the incline with constant velocity, so it is in equilibrium. The bracket exerts a normal force $N=mg\cos \theta$ and a friction/contact force $N^{\prime }=mg\sin \theta$ along the incline on the block.

Total force of the bracket on the block: $R=\sqrt{N^2+N^{\prime 2}}=mg$, balancing the weight.