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Physics - NLM Question with Solution | TestHub

PhysicsNLMFrictionMedium2 minQB

PhysicsMediumsingle choice

Passage / Comprehension

In diagram, the friction coefficient between the block of mass 1 kg and the plank of mass 2 kg is 0.4 while that between the plank and floor is 0.1. A constant force 'F' starts acting horizontally on the upper 1 kg block.

For what value of F will the block move with double the acceleration of that of the plank?

Options:

Answer:

Solution:

Acceleration of block $F - 4 = a$

Acceleration of plank $= \frac{1}{2} m / s^{2}$

According to situation $F - 4 = 1 \Rightarrow F = 5 N$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Friction

⏱ 2mℹ️ Source: QB

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