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PhysicsNLMMiscellaneousEasy2 minPYQ_2020
PhysicsEasysingle choice

a marble block of mass 2 kg lying on the ice when given a velocity of  6 m s−1 is stopped by frictional force in 10 s. Then the coefficient of friction is 
(take g=10 m s-2)

Options:

Answer:
D
Solution:

     v=u+at       v=u−μgt                             ( since   μmg=ma )      0=6−μ×10×10 or  100μ=6 or  μ=6100=0.06

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:NLMSubtopic:Miscellaneous
⏱ 2mℹ️ Source: PYQ_2020

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