An elevator cabin has a mass of 900 kg (excluding man's mass) A man is standing in it. When the cabin is pulled upwards with a force of 7000 N, the man feels a normal force of 700 N on his feet.

Question

An elevator cabin has a mass of 900 kg (excluding man's mass) A man is standing in it. When the cabin is pulled upwards with a force of 7000 N, the man feels a normal force of 700 N on his feet. How much normal force (in N) will he feel if we pull the cabin upward with a force of 10,000 N.

TestHub · Accepted Answer

First case: 7000 − ( 900 + m ) g = ( 900 + m ) a , and for the man 700 − m g = ma Combining: 7000 − 9000 − 700 = 900 a , so a = − 3 m/s 2 700 = m ( 10 − 3 ) , giving the man's mass m = 100 kg Second case: 10000 − 1000 × 10 = 1000 a ′ , so a ′ = 0 N ′ = m g = 1000 N

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