Two blocks of mass 2 kg and 4 kg are connected through a massless inextensible string. Coefficient of friction between 2 kg block and ground is 0.4 and between 4 kg block and ground is 0.6. Force of 80N is applied on the 4kg block as shown in figure. The acceleration of the system is
$. 4^{kg}$
$= 0.4$
$= 0.6$

Question

Two blocks of mass 2 kg and 4 kg are connected through a massless inextensible string. Coefficient of friction between 2 kg block and ground is 0.4 and between 4 kg block and ground is 0.6. Force of 80N is applied on the 4kg block as shown in figure. The acceleration of the system is

$. 4^{kg}$

$= 0.4$

$= 0.6$

TestHub · Accepted Answer

Friction forces: 0.6 × 40 = 24 N on the 4 kg block and 0.4 × 20 = 8 N on the 2 kg block 80 − 24 − 8 = ( 2 + 4 ) a a = 6 48 ​ = 8 m/s 2

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