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Physics - NLM Question with Solution | TestHub

PhysicsNLMMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A man stands on a weighing machine kept inside a lift. Initially, the lift is ascending with the acceleration $a$ due to which the reading is $W$ . Now the lift descends with the same acceleration and reading is $10 %$ of initial. Find the acceleration of lift.

Options:

Answer:

Solution:

$N = m (g + a)$

$N^{'} = m (g - a)$

$N^{'} = \frac{10}{100} \times N$

$m (g - a) = \frac{m (g + a)}{10}$

$10 g - 10 a = g + a$

$9 g = 11 a$

$\Rightarrow a = \frac{9 g}{11}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:NLMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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