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Physics - NLM Question with Solution | TestHub

PhysicsNLMSimple Application of NLMEasy2 minQB

PhysicsEasysingle choice

Three blocks A, B, C of mass 2kg, 3kg, 5kg are placed on a frictionless inclined as shown in figure. Force F of magnitude 150 N is applied on block 'C' as shown. Find tension in string 1( $T_{1}$ ) :-

Options:

Answer:

Solution:

$150 - 10 \times 10 \times 1/2 = 10 a$

$100 = 10 a a = 10 m / s^{2}$

For whole system

$T - 10 = 2 (10) T = 30 N$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:Simple Application of NLM

⏱ 2mℹ️ Source: QB

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