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PhysicsNLMMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

Two blocks ' $A$ ' and ' $B$ ' each of mass ' $m$ ' are placed on a smooth horizontal surface. Two horizontal forces $F$ and $2 F$ are applied on the blocks $A$ and $B$ , respectively, as shown in figure. The block $A$ does not slide on block $B$ . The normal reaction acting between the two blocks is

Options:

Answer:

Solution:

Acceleration of two mass system is $a = \frac{F}{2 m}$ leftward

FBD of block $A$

$N \cos 60^{o} - F = m a$

$\Rightarrow N \cos 60^{o} - F = \frac{m F}{2 m}$

$\Rightarrow N = 3 F$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:NLMSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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