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PhysicsNLMMiscellaneousEasy2 minPYQ_2020
PhysicsEasysingle choice

In the figure,mA=2 kgandmB=4 kg. For what minimum value ofF,Astarts slipping overB g=10m s-2?

Options:

Answer:
B
Solution:

Maximum frictional force betweenAandBcould be

f1=μ1mAg=0.2210 N

f1=4 N

Acceleration when frictional force is maximum,

a=f1mA

a=42=2m/s2

Fictional force between ground and B

f2=μ2mA+mBg

f2=0.42+410

f2=24 N



Therefore for the entire system,

F-f2=mA+mBa

F-24=2+42

F=36 N

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:NLMSubtopic:Miscellaneous
⏱ 2mℹ️ Source: PYQ_2020

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