Physics - NLM Question with Solution | TestHub

PhysicsNLMMedium2 minQB

PhysicsMediummultiple choice

In the system shown in the figure $m_{1} > m_{2}$ . System is held at rest by thread BC. Just after the thread BC is burnt:

Answer:

A, C

Solution:

$Kx = m_{1} g = T$

On cutting string, tension remains unchanged.

$\Rightarrow m_{1} g - m_{1} g = m_{1} a_{1}$

$a_{1} = 0 a = \frac{T - m _{2} g}{m _{2}} ↑ a = \frac{( m _{1} - m _{2} )}{m _{2}} g ↑$

Stream:JEESubject:PhysicsTopic:NLM

⏱ 2mℹ️ Source: QB

Loading discussions...