A block of mass 'M' is moving on rough horizontal surface with momentum 'P'. The coefficient of friction between the block and surface is ' μ '. The distance covered by b

Question

A block of mass 'M' is moving on rough horizontal surface with momentum 'P'. The coefficient of friction between the block and surface is ' μ '. The distance covered by block before it stops is [ g = acceleration due to gravity ]

TestHub · Accepted Answer

Using kinematic relation, v 2 = u 2 − 2 a s The momentum pis given by p = M u u = M P ​ ​ and acceleration is given as a = μg Substituting values in Eq. (i), we get 0 = u 2 − 2 as ( ∵ f ∈ alvelocity , v = 0 ) 0 = ( M p ​ ) 2 − 2 μ gs ( M p ​ ) 2 = 2 μ gs ⇒ s = 2 M 2 μ g p 2 ​ ​

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