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PhysicsNLMFBD & EquilibriumMedium2 minPYQ_2018

PhysicsMediumsingle choice

In the diagram $100 kg$ block is hanging from a pulley and force $F$ is applied on the string to keep the system in equilibrium. If the whole system is moving up with a constant velocity $v$ , then tension at point $P$ in the string will be

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Solution:

Tension in each part of the string will be F. Assume tension at point $P$ is $T$ .
$T = 3 F 2 F = m g 2 F = 100 \times 9.8 N F = 490 N ∴ T = 3 \times 490 = 1470 N$

Stream:AIIMSSubject:PhysicsTopic:NLMSubtopic:FBD & Equilibrium

⏱ 2mℹ️ Source: PYQ_2018

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