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PhysicsNLMFBD & EquilibriumEasy2 minPYQ_2023

PhysicsEasysingle choice

A block of $\sqrt{3} kg$ is attached to a string whose other end is attached to the wall. An unknown force $F$ is applied so that the string makes an angle of $30 °$ with the wall. The tension $T$ is : (Given g $= 10 m s^{- 2}$ )

Options:

Answer:

Solution:

From geometry, $θ = 30 °$ .

For equilibrium,

$T \cos θ = m g$

$\Rightarrow T = \frac{m g}{\cos 30 °} \Rightarrow T = \frac{\sqrt{3} \times 10}{\frac{\sqrt{3}}{2}}$

$\Rightarrow T = 20 N$

Stream:JEESubject:PhysicsTopic:NLMSubtopic:FBD & Equilibrium

⏱ 2mℹ️ Source: PYQ_2023

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