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PhysicsNLMFBD & EquilibriumEasy2 minPYQ_2020
PhysicsEasysingle choice

A horizontal rod of mass0.01 kgand length10 cmis placed on a frictionless plane inclined at an angle60°with the horizontal and with the length of the rod parallel to the edge of the inclined plane. A uniform magnetic field is applied vertically downwards. If the current through the rod is1.73 A, then the value of magnetic field inductionBfor which the rod remains stationary on the inclined plane is

Options:

Answer:
A
Solution:

Here two forces are acting on the rod simultaneously. From the hypothetical free body diagram.



mgsin⁡60=Bilcos⁡60o

B=mgiltan⁡60o

=0.01×101.73×0.1×3

B=1 T

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:NLMSubtopic:FBD & Equilibrium
⏱ 2mℹ️ Source: PYQ_2020

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