1 0 23 molecules of a gas, each having a mass of 3 × 1 0 − 27 kg strike per second per sq.cm of a rigid wall at an angle of 6 0 ∘ with the normal and rebound with a velocity of 500 m / s . The pressure exerted by the gas molecules on the wall is

According to the Newton's second law of motion: Pressure exerted on the wall = Area Rate of change of mometum × no. of molecules ⇒ P = A ( 2 mV cos 6 0 ∘ ) × N = 1 0 − 4 2 × 3 × 1 0 − 27 × 5 × 1 0 − 2 × cos 6 0 ∘ × 1 0 23 ∴ P = 1500 N / m 2

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Physics - NLM Question with Solution | TestHub

PhysicsNLMSimple Application of NLMMedium2 minPYQ_2022

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$1 0^{23}$ molecules of a gas, each having a mass of $3 \times 1 0^{- 27} kg$ strike per second per sq.cm of a rigid wall at an angle of $6 0^{\circ}$ with the normal and rebound with a velocity of $500 m / s$ . The pressure exerted by the gas molecules on the wall is

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According to the Newton's second law of motion: $Pressure exerted on the wall = \frac{Rate of change of mometum \times no. of molecules}{Area} \Rightarrow P = \frac{( 2 mV cos 6 0 ^{\circ} ) \times N}{A} = \frac{2 \times 3 \times 1 0 ^{- 27} \times 5 \times 1 0 ^{- 2} \times cos 6 0 ^{\circ} \times 1 0 ^{23}}{1 0 ^{- 4}} ∴ P = 1500 N / m^{2}$

Stream:MHT_CETSubject:PhysicsTopic:NLMSubtopic:Simple Application of NLM

⏱ 2mℹ️ Source: PYQ_2022

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