A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring balance reads 49 N , when the lift is stationary. If the lift moves downward with an acceleratio

Question

A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring balance reads $49 N$ , when the lift is stationary. If the lift moves downward with an acceleration of $5 m / s^{2}$ , the reading of the spring balance will be

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Answer:

C

Solution:

$W = 49 N ∴ m = \frac{W}{g} = \frac{49}{9.8} = 5 kg W^{'} = W - ma = 49 - 5 \times 5 = 49 - 25 = 24 N$

TestHub · Accepted Answer

​ W = 49 N ∴ m = g W ​ = 9.8 49 ​ = 5 kg W ′ = W − ma = 49 − 5 × 5 = 49 − 25 = 24 N ​

Physics - NLM Question with Solution | TestHub

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