A mass of 1 kg is suspended by means of a thread. The system is (i) lifted up with an acceleration of 4.9 ms − 2 (ii) lowered with an acceleration of 4.9 ms − 2 . The ratio of tension in the first and

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A mass of 1 kg is suspended by means of a thread. The system is (i) lifted up with an acceleration of 4.9 ms − 2 (ii) lowered with an acceleration of 4.9 ms − 2 . The ratio of tension in the first and second case is

TestHub · Accepted Answer

When the body of mass m lifted up the forces acting on the body T 1 ​ − m g T 1 ​ ​ = 2 m g ​ = m g + 2 m g ​ = 2 3 m g ​ ​ (ii) When the body lowered the acting forces ( m g − T 2 ​ ) = 2 m g ​ T 2 ​ = m g − 2 m g ​ = 2 m q ​ ∴ T 2 ​ T 1 ​ ​ ​ = m g /2 3 m g /2 ​ = 1 3 ​ = 3 : 1 ​

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