Physics - NLM Question with Solution | TestHub

According to conservation of linear momentum, $m_1{v}_1=m_{1}v+m_2{v}_2$ where $v_1$ is velocity of bullet before collision, $v$ is velocity of bullet after the collision and $v_2$ is the velocity of block. $\therefore 0.02\times 600=0.02v+4v_2$ Here, $v_2=\sqrt{2\mathrm{gh}}=\sqrt{2\times 10\times 0.2}=2\mathrm{m}/\mathrm{s}$ $\therefore 0.02\times 600=0.02v+4\times 2$ $\Rightarrow 0.02v=12-8$ $\Rightarrow v=\frac{4}{0.02}=200\mathrm{m}/\mathrm{s}$