Start Free Mock LoginAlready registered? Login here

Physics - NLM Question with Solution | TestHub

PhysicsNLMFBD & EquilibriumMedium2 minai-gemini

PhysicsMediumsingle choice

A mass $m$ is suspended from the ceiling by two light strings of lengths $L_{1}$ and $L_{2}$ . The strings make angles $θ_{1}$ and $θ_{2}$ with the horizontal respectively. If the tension in the string of length $L_{1}$ is $T_{1}$ and in $L_{2}$ is $T_{2}$ , then the ratio $T_{1} / T_{2}$ is:

Options:

Answer:

Solution:

For the mass to be in equilibrium, the net force on it is zero. Resolving forces horizontally: The horizontal components of the tensions must balance. $T_{1} cos θ_{1} = T_{2} cos θ_{2}$ . From this equation, the ratio $T_{1} / T_{2} = \frac{c o s θ _{2}}{c o s θ _{1}}$ .

Stream:JEESubject:PhysicsTopic:NLMSubtopic:FBD & Equilibrium

⏱ 2mℹ️ Source: ai-gemini

Doubts & Discussion

Loading discussions...