When a metal surface is illuminated with light of wavelength λ , the stopping potential is V 0 . When the same surface is illuminated with light of wavelength 2 λ , the stopping potential is 4 V 0

Question

When a metal surface is illuminated with light of wavelength λ , the stopping potential is V 0 ​ . When the same surface is illuminated with light of wavelength 2 λ , the stopping potential is 4 V 0 ​ ​ . If the velocity of light in air is c, the threshold frequency of photoelectric emission is

TestHub · Accepted Answer

​ e V 0 ​ = λ h c ​ − h ν 0 ​ ​ 4 e V 0 ​ ​ = 2 λ h c ​ − h ν 0 ​ ​ Elimination gives ​ 3 h ν 0 ​ = λ h c ​ ​ ν 0 ​ = 3 λ c ​ ​

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