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PhysicsModern PhysicsAtomic structureMedium2 minPYQ_2019

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The electron in a hydrogen atom first jumps from the third excited state to the second excited state and subsequently to the first excited state. The ratio of the respective wavelengths $\frac{λ_{1}}{λ_{2}}$ of the photons emitted in this process is:

Options:

Answer:

Solution:

$\frac{1}{λ_{1}} = R (\frac{1}{3^{2}} - \frac{1}{4^{2}}) = \frac{R \times 7}{144}$
$\frac{1}{λ_{2}} = R (\frac{1}{2^{2}} - \frac{1}{3^{2}}) = \frac{R \times 5}{36}$
$\Rightarrow \frac{λ_{1}}{λ_{2}} = \frac{R \times 5}{36} \times \frac{144}{R \times 7} = \frac{20}{7}$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2019

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