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PhysicsModern PhysicsDe Broglie & Matter WavesMedium2 minPYQ_2021

PhysicsMediumstatement

The de Broglie wavelength of a proton and $α$ -particle are equal. The ratio of their velocities is

Answer:

Solution:

$λ = \frac{h}{m v}$

$λ_{p} = λ_{α}$

$m_{P} V_{P} = m_{α} v_{α}$

$m_{P} v_{P} = 4 m_{p} v_{α}$ $(m_{α} = 4 m_{P})$

$\frac{v_{p}}{v_{α}} = 4$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2021

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