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PhysicsModern PhysicsAtomic structureMedium2 minQB

PhysicsMediumsingle choice

The energy of $H e^{+}$ ion in its first state is, (The ground state energy for the Hydrogen atom $- 13.6 e V$ ):

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Answer:

Solution:

Energy of Hydrogen like atoms is, $E = \frac{- 13.6 Z ^{2}}{n ^{2}} e V$ .
Since Helium is in the first state, $Z = 2, n = 2$ .
The energy of $H e^{+}$ ion is,
$E = - \frac{13.6 \times 2 ^{2}}{2 ^{2}} = - 13.6 e V$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: QB

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