A nucleus of mass M at rest splits into two parts having masses M ' 3 and 2 M ' 3 M ' < M . The ratio of de Broglie wavelength of two parts will be

Since the initial momentum of the system is zero. To keep the final momentum zero, the momentum of both parts should be equal and opposite in direction. P → 1 = P → 2 Here P → is momentum De-Broglie wavelength is given by λ = h P Hence, both will have same de Broglie wavelength. Therefore, λ 1 : λ 2 = 1 : 1 .

Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsDe Broglie & Matter WavesMedium2 minPYQ_2022

PhysicsMediumstatement

A nucleus of mass $M$ at rest splits into two parts having masses $\frac{M^{'}}{3}$ and $\frac{2 M^{'}}{3} (M^{'} < M)$ . The ratio of de Broglie wavelength of two parts will be

Options:

Answer:

Solution:

Since the initial momentum of the system is zero. To keep the final momentum zero, the momentum of both parts should be equal and opposite in direction.
$|{\vec{P}}_{1}| = |{\vec{P}}_{2}|$
Here $\vec{P}$ is momentum
De-Broglie wavelength is given by $λ = \frac{h}{P}$
Hence, both will have same de Broglie wavelength.
Therefore, $λ_{1} : λ_{2} = 1 : 1$ .

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: PYQ_2022

Doubts & Discussion

Loading discussions...