(C) U i = 0 + 0 U f = − mgx + 2 1 kx 2 = − 1 × 10 × 0.1 + 2 1 × 100 × ( 0.1 ) 2 = 2 − 1 J (D) Potential energy of water ↑ Potential energy of block ↓

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PhysicsModern PhysicsMiscellaneousMedium2 minQB

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Answer:

Solution:

$U_{f} = - mgx + \frac{1}{2} kx^{2}$

$= - 1 \times 10 \times 0.1 + \frac{1}{2} \times 100 \times (0.1)^{2} = \frac{- 1}{2} J$

(D) Potential energy of water $↑$

Potential energy of block $↓$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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