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PhysicsModern PhysicsAtomic structureEasy2 minQB

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Considering the Bohr model of hydrogen like atoms, the ratio of the ratio of the radius $5^{th}$ orbit of the electron in $Li^{2 +}$ and $He^{+}$ is

Answer:

Solution:

$r = r \cdot \frac{n ^{2}}{2}$

for $Li^{2 +}$

$r_{5} = r \cdot \frac{25}{3}$

for $He^{+}$

$r_{5} = r \cdot \frac{25}{2} ∴ \frac{r _{Li^{2 +}}}{r _{He^{+}}} = \frac{2}{3}$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: QB

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