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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsX-raysHard2 minPYQ_2022

PhysicsHardsingle choice

The glancing angle in a X-rays diffraction experiment is $3 0^{\circ}$ and the wavelength of the $X$ rays used is $20 mm$ . The interplanar spacing of the crystal diffracting these X-rays will be

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Solution:

Using formula $2 d sin θ = n λ d = \frac{n λ}{2 sin θ} = \frac{1 \times 20 \times 1 0 ^{- 3}}{2 sin 3 0 ^{\circ}}$ $d = \frac{20 \times 1 0 ^{- 3}}{2 \times \frac{1}{2}} = 20 nm$

Stream:VITEEESubject:PhysicsTopic:Modern PhysicsSubtopic:X-rays

⏱ 2mℹ️ Source: PYQ_2022

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