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PhysicsModern PhysicsNuclear physicsMedium2 minQB

PhysicsMediummultiple choice

The $^{238} U$ nucleus has a binding energy of about 7.6 MeV per nucleon. If the nucleus were to fission into two equal fragments , each would have a kinetic energy of just over 100 MeV. From this , it can be concluded that :-

Options:(select one or more)

Answer:

A, D

Solution:

Energy released 200 MeV: $200 = 238 E - 238 \times 7.6$ gives $E \approx 8.5$ MeV/nucleon (D)

Fragments are more tightly bound, so mass of A ≈ 119 nucleus < half of U-238 (A)

Answers (A, D)

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Nuclear physics

⏱ 2mℹ️ Source: QB

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