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E(K${}_{\alpha }$) + E(L${}_{\beta }$) = E(K${}_{\beta }$) + E(M${}_{\alpha }$) = E(K${}_{\gamma }$)

For the harder X-rays, the intensity is higher then soft X-rays

The continuous and the characteristic X-rays of same wavelengths differ only in the method of creation

The cut-off wavelength${\lambda }_{\min }$depends only on the accelerating voltage applied between the target and the filament.