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Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsNuclear physicsMedium2 minQB

PhysicsMediumsingle choice

Energy released in fission of single $_{92} U^{235}$ nucleus is 200 MeV . The fission rate of $_{92} U^{235}$ fuelled reactor operating at power of 5W is:-

Options:

Answer:

Solution:

Energy per fission: $200 MeV = 3.2 \times 1 0^{- 11} J$

Fission rate: $\frac{P}{E} = \frac{5}{3.2 \times 1 0 ^{- 11}}$

$= 1.56 \times 1 0^{11} s^{- 1}$

Option (B)

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Nuclear physics

⏱ 2mℹ️ Source: QB

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