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PhysicsModern PhysicsAtomic structureMedium2 minQB

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In the spectrum of hydrogen, what is the ratio of the longest wavelength in the Lyman series $(n_{f} = 1)$ to the longest wavelength in the Balmer series $(n_{f} = 2)$ ?

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Answer:

Solution:

Longest Lyman: $\frac{1}{λ _{L}} = R (1 - \frac{1}{4}) = \frac{3 R}{4}$ ; longest Balmer: $\frac{1}{λ _{B}} = R (\frac{1}{4} - \frac{1}{9}) = \frac{5 R}{36}$ . $\frac{λ _{L}}{λ _{B}} = \frac{5 R /36}{3 R /4} = \frac{5}{27}$ .

Subject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: QB

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