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PhysicsModern PhysicsNuclear physicsHard2 minPYQ_2024
PhysicsHardnumerical

In a nuclear fission process, a high mass nuclide(A236)with binding energy7.6 MeV/Nucleon dissociated into two middle mass nuclides(A118), having binding energy of8.6 MeV/Nucleon. The energy released in the process would be _______MeV.

Answer:
236.00
Solution:

The formula to calculate the energy released in the given process can be written as

Q=BEProduct -BEReactant    ...1

From equation (1), it follows that

Q=2(118)(8.6)-236(7.6) MeV=236 MeV

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Nuclear physics
2mℹ️ Source: PYQ_2024

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