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PhysicsModern PhysicsDe Broglie & Matter WavesMedium2 minQB

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What is the de Broglie wavelength of the $α$ -particle accelerated through a potential difference V?

Answer:

Solution:

$λ = \frac{h}{2 m _{α} ( 2 e ) V}$ ; putting $m_{α} = 4$ u gives $λ = \frac{0.101}{V} \overset{˚}{A}$ .

Subject:PhysicsTopic:Modern PhysicsSubtopic:De Broglie & Matter Waves

⏱ 2mℹ️ Source: QB

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