Nucleus a having Z = 17 and equal number of protons and neutrons has 1.2 M e V binding energy per nucleon. Another nucleus B of Z = 12 has total 26 nucleons and 1.8 M e V binding energy per nucleons.

Question

Nucleus a having Z = 17 and equal number of protons and neutrons has 1.2 M e V binding energy per nucleon. Another nucleus B of Z = 12 has total 26 nucleons and 1.8 M e V binding energy per nucleons. The difference of binding energy of B and A will be ______ M e V .

TestHub · Accepted Answer

In A , Z = 17 and have equal numbers of protons and neutrons i.e. nucleons = 2 × 17 = 34 So, for A , Total binding energy B E A ​ = 1.2 × 34 = 40.8 M e V Another nucleus B mass number = 26 So, total binding energy of B is B E B ​ = 1.8 × 26 M e V = 46.8 M e V Difference of BE = B E B ​ − B E A ​ = 6 M e V

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