The ionization energy of the electron in the hydrogen atom in its grounds state is 13.6 eV . The atoms are excited to higher energy levels to emit radiations of 6 wavelengths. Maximum wavelength of em

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The ionization energy of the electron in the hydrogen atom in its grounds state is 13.6 eV . The atoms are excited to higher energy levels to emit radiations of 6 wavelengths. Maximum wavelength of emitted radiation corresponds to the transition between :NEET 2009 (Mains)

TestHub · Accepted Answer

⇒ ​ 2 n ( n − 1 ) ​ = 6 n = 4 ​ For maximum wavelength energy difference between states should be minimum because λ = Δ E hc ​ So, transition state in n = 4 to n = 3

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