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PhysicsModern PhysicsNuclear physicsMedium2 minPYQ_2016

PhysicsMediumsingle choice

When an $α$ -particle of mass $m$ moving with a undefined velocity bombards on a heavy nucleus of charge $Ze$ , its distance of the closest approach from the nucleus depends on $m$ as:NEET 2016 (Phase 1)

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Answer:

Solution:

At the distance of the lowest approach, total K.E. of $α$ -particle changes to P.E. So,
$\frac{1}{2} m v^{2} = \frac{K Q . q}{r} = \frac{K (Z e) (2 e)}{r}$
$r = \frac{4 K Z e^{2}}{m v^{2}} \Rightarrow r \propto \frac{1}{m}$
$r \propto \frac{1}{m}$

Stream:NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Nuclear physics

⏱ 2mℹ️ Source: PYQ_2016

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