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PhysicsModern PhysicsAtomic structureEasy2 minPYQ_2024
PhysicsEasynumerical

The mass defect in a particular reaction is 0.4 g. The amount of energy liberated is n×107 kW h, where n= _____. (speed of light =3×108 m s-1)

Answer:
1.00
Solution:

Energy liberated is given by, E=mc2

=0.4×10-3×3×1082

=3600×107 kW s

=3600×1073600 kW h=1×107 kW h

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure
2mℹ️ Source: PYQ_2024

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