TestHub
TestHub

Physics - Modern Physics Question with Solution | TestHub

PhysicsModern PhysicsPhotoelectric effectHard2 minPYQ_2018
PhysicsHardnumerical

In a photoelectric experiment, a parallel beam of monochromatic light with the power of 200W is incident on a perfectly absorbing cathode of work function6.25 eV. The frequency of light is just above the threshold frequency so that the photoelectrons are emitted with negligible kinetic energy. Assume that the photoelectron emission efficiency is 100%. A potential difference of 500V is applied between the cathode and the anode. All the emitted electrons are incident normally on the anode and are absorbed. The anode experiences a forceF=n×10-4 Ndue to the impact of the electrons. The value of n is __________. Mass of the electronme=9×10-31 kg and 1.0 eV=1.6×10-19 J.

Answer:
24.00
Solution:

Power=Nhν
N=number of photons per second
SinceKE=0,hν=ϕ
200=N6.25×1.6×10-19  Joule
N=2006.25×1.6×10-19
As photon is just above threshold frequencyKEmaxis zero and they are accelerated by potential difference of500 V
KEf=qV
P22m=qVP=2mqV
Since efficiency is 100%, number of electrons emitted is equal to number of photons falling per second as electrons are completely absorbed, force exertednmv
= 2006.25×1.6×10-19×29×10-31×1.6×10-19×500
= 3×200×10-25×16006.25×1.6×10-19=2×406.25×1.6×10-4×3=24 × 10 4
n=24

Stream:JEE_ADVSubject:PhysicsTopic:Modern PhysicsSubtopic:Photoelectric effect
2mℹ️ Source: PYQ_2018

Doubts & Discussion

Loading discussions...