Nucleus a having Z = 17 and equal number of protons and neutrons has 1 . 2 MeV binding energy per nucleon. Another nucleus B of Z = 12 has total 26 nucleons and 1 . 8 MeV binding energy per nucleons.

Question

Nucleus a having Z = 17 and equal number of protons and neutrons has 1 . 2 MeV binding energy per nucleon. Another nucleus B of Z = 12 has total 26 nucleons and 1 . 8 MeV binding energy per nucleons. The difference of binding energy of B and A will be ______ MeV .

TestHub · Accepted Answer

In A , Z = 17 and have equal numbers of protons and neutrons i.e. nucleons = 2 × 17 = 34 So, for A , Total binding energy B E A = 1 . 2 × 34 = 40 . 8 MeV Another nucleus B mass number = 26 So, total binding energy of B is B E B = 1 . 8 × 26 MeV = 46 . 8 MeV Difference of B E = B E B - B E A = 6 MeV

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