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PhysicsModern PhysicsAtomic structureMedium2 minPYQ_2025

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An electron projected perpendicular to a uniform magnetic field B moves in a circle. If Bohr's quantization is applicable, then the radius of the electronic orbit in the first excited state is :

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Answer:

Solution:

$m v r = \frac{nh}{2 π}$ ...(i) $r = \frac{v m}{Bq}$ ....(ii) $n = 2 m r (\frac{r Bq}{m}) = \frac{2 h}{2 π} r = \frac{h}{π Bq} q = e r = \frac{h}{π B e}$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2025

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