The photoelectric threshold frequency of metal is ν . When the light of frequency 4 ν is incident on the metal, the maximum kinetic energy of the emitted photoelectrons is

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TestHub · Accepted Answer

From Einstein's photoelectric equation the maximum kinetic energy of photoelectrons emitted from the metal surface is given by

$E_{k} = h ν_{1} - W$

Where $W$ is the work function of the metal.

Given, $W = h ν$ and $ν_{1} = 4 ν$

$∴ E_{k} = 4 h ν - h ν = 3 h ν$

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