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PhysicsModern PhysicsAtomic structureMedium2 minPYQ_2023

PhysicsMediumsingle choice

The energy of ${He}^{+}$ ion in its first state is, (The ground state energy for the Hydrogen atom $- 13.6 eV$ ):

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Answer:

Solution:

Energy of Hydrogen like atoms is, $E = \frac{- 13.6 Z^{2}}{n^{2}} eV$ .
Since Helium is in the first state, $Z = 2, n = 2$ .
The energy of ${He}^{+}$ ion is,
$E = - \frac{13.6 \times 2^{2}}{2^{2}} = - 13.6 eV$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2023

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