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PhysicsModern PhysicsAtomic structureMedium2 minPYQ_2025

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De-Broglie wavelength of an electron orbiting in the $n = 2$ state of hydrogen atom is close to (Given Bohr radius $= 0.052 nm$ )NEET 2025

Answer:

Solution:

Given $n = 2, Z = 1$ $2 π r = n λ 2 π \times (0.052 \frac{n ^{2}}{Z}) = n λ$ On solving $λ = 0.67 nm$

Stream:NEETSubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: PYQ_2025

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