Physics - Modern Physics Question with Solution | TestHub

Concept: Stopping potential $V$ is related to the maximum kinetic energy $K_{\max }$ of the photoelectrons, via Einstien's photo-electric effect relation: $eV=K_{\max }=hv-h{v}_0$ Therefore, $V=\left(\frac{h}{e}\right)v-\left(\frac{h}{e}\right)v_0$ Therefore, $V$ vs $v$ is straighline with positive slope and at $v=v_0$ the stopping potential is zero.