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PhysicsModern PhysicsAtomic structureEasy2 minQB

PhysicsEasysingle choice

For a hydrogen atom, the ratio of the largest wavelength of Lyman series to that of the Balmer series is.

Answer:

Solution:

$Lyman$

$\frac{1}{λ _{1}} = R [\frac{1}{1} - \frac{1}{4}] = \frac{3 R}{4}$

$λ_{1} = \frac{4}{3 R}$ ________...(1)

and $Balmer$

$\frac{1}{λ _{2}} = R [\frac{1}{4} - \frac{1}{9}] = \frac{5 R}{36}$

$λ_{2} = \frac{36}{5 R}$

Then, $\frac{λ _{1}}{λ _{2}} = \frac{5}{27}$

Stream:JEESubject:PhysicsTopic:Modern PhysicsSubtopic:Atomic structure

⏱ 2mℹ️ Source: QB

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